The Sum Of Three Consecutive Multiples Of 8 Is 888

The Sum Of Three Consecutive Multiples Of 8 Is 888. Then second consecutive multiple of 8 will be x + 8. Let the first multiple be x. Let the three consecutive multiples of 8 be 8x, 8(x+1) and 8(x+2). Let's form a linear equation for the given problem statement. Find the multiples hard solution verified by toppr let 3 consecutive multiple of 8 8x,8(x+1),8(x+2) sum=8x+8(x+1)+8(x+2)=888. We have to find the multiples. Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x + 2).

Best answer let the three consecutive multiples of 8 be x, x+8 and x+16. Thus, the multiples are 288, 296 and 304. (a) 120, 136, 400 (b) 110, 121, 132 (c) 110, 99, 154 (d) none of these advertisement answer 5.0 /5 5. The sum of three concetive multiples of 8 is 888.find the multiples. The multiples of 8 are in the format of 8n. Best answer let the three consecutive multiples of 8 be 8x, 8 (x + 1), 8 (x + 2). Then second consecutive multiple of 8 will be x + 8.

Best answer let the three consecutive multiples of 8 be x, x+8 and x+16.

On dividing both sides by. 28,569 views sep 14, 2020 the sum of three consecutive multiples of 8 is 888. Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x+ 2). The sum of three consecutive multiples of 8 is 888. Answer :sum of three consecutive multiples is 888. According to question, x+x+8+x+16=888 [subtracting 24 from both sides] => 3x=864 =>. Sum of these numbers = 8x + 8 (x + 1) + 8 (x + 2) = 888 8 (x + x + 1 + x + 2) = 888 8 (3x + 3) =. Let the first multiple be x.

Then Second Consecutive Multiple Of 8 Will Be X + 8.

28,569 views sep 14, 2020 the sum of three consecutive multiples of 8 is 888. According to question, x+x+8+x+16=888 [subtracting 24 from both sides] => 3x=864 =>. Let's form a linear equation for the given problem statement. Best answer let the three consecutive multiples of 8 be x, x+8 and x+16. The sum of 3 consecutive multiples of 8 is 888. Answer :sum of three consecutive multiples is 888.

Let The Three Consecutive Multiples Of 8 Be 8X, 8(X + 1), 8(X + 2).

The sum of three consecutive multiples of 8 is 888. Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x+ 2). Find the multiples 34,314 views apr 14, 2017 class 8th, maths ex 2.2 q 7 677 dislike share save gyan abhiyan 81.6k subscribers. ⇒ 8 x + 8 ( x + 1) + 8 ( x + 2) = 888 ⇒ 8 x + 8 x + 8 x + 8 + 16 = 888 ⇒ 24 x + 24 = 888. 8(x + x + 1 + x + 2) = 888. .more.more dislike share maths doubt 33.6k subscribers comments.

Conclusion of The Sum Of Three Consecutive Multiples Of 8 Is 888.

⇒ 8 x + 8 ( x + 1) + 8 ( x + 2) = 888 ⇒ 8 x + 8 x + 8 x + 8 + 16 = 888 ⇒ 24 x + 24 = 888. The sum of 3 consecutive multiples of 8 is 888.. The sum of three consecutive multiple of 8 is 888. Sum of these numbers = 8x + 8 (x + 1) + 8 (x + 2) = 888 8 (x + x + 1 + x + 2) = 888 8 (3x + 3) =.

Click here to preview your posts with PRO themes ››

Source